Seth, Brandon and Daniel have some stamps. The ratios of their stamps are as follows:

Seth : (Seth + Brandon + Daniel) = 1 : 4
Brandon : (Seth + Daniel) = 1 : 5

Daniel has 55 stamps more than Brandon. In the end, Daniel gives away all he has to Brandon and Seth so that both Brandon and Seth end up with the same number of stamps, how many stamps has Seth received from Daniel?

Brandon	Daniel	Seth	Total
3x3		1x3	4x3
1x2	5x2		6x2
2 u	7 u	3 u	12 u

The total number of stamps is repeated.  Make the total number of stamps the same.  LCM of 4 and 6 is 12.

Number of stamps that Daniel has more than Brandon
= 7 u - 2 u
= 5 u

5 u = 55

1 u = 55 ÷ 5 = 11

	Brandon	Daniel	Seth
Before	2 u	7 u	3 u
Change	+ 4 u	- 7 u	+ 3 u
After	6 u	0 u	6 u

Number of stamps that Seth has received from Daniel
= 6 u - 3 u 
= 3 u
= 3 x 11
= 33

Answer(s): 33