Lee, Tommy and Bryan have some coins. The ratios of their coins are as follows:
Lee : (Lee + Tommy + Bryan) = 1 : 5
Tommy : (Lee + Bryan) = 1 : 3
Bryan has 42 coins more than Tommy. In the end, Bryan gives away all he has to Tommy and Lee so that both Tommy and Lee end up with the same number of coins, how many coins has Lee received from Bryan?
Tommy |
Bryan |
Lee |
Total |
4x4 |
1x4 |
5x4 |
1x5 |
3x5 |
4x5 |
5 u |
11 u |
4 u |
20 u |
The total number of coins is repeated. Make the total number of coins the same. LCM of 5 and 4 is 20.
Number of coins that Bryan has more than Tommy
= 11 u - 5 u
= 6 u
6 u = 42
1 u = 42 ÷ 6 = 7
|
Tommy |
Bryan |
Lee |
Before |
5 u |
11 u |
4 u |
Change |
+ 5 u |
- 11 u |
+ 6 u |
After |
10 u |
0 u |
10 u |
Number of coins that Lee has received from Bryan
= 10 u - 4 u
= 6 u
= 6 x 7
= 42
Answer(s): 42