Nick, Tim and Pierre have some marbles. The ratios of their marbles are as follows:
Nick : (Nick + Tim + Pierre) = 1 : 5
Tim : (Nick + Pierre) = 1 : 5
Pierre has 154 marbles more than Tim. In the end, Pierre gives away all he has to Tim and Nick so that both Tim and Nick end up with the same number of marbles, how many marbles has Tim received from Pierre?
Tim |
Pierre |
Nick |
Total |
4x6 |
1x6 |
5x6 |
1x5 |
5x5 |
6x5 |
5 u |
19 u |
6 u |
30 u |
The total number of marbles is repeated. Make the total number of marbles the same. LCM of 5 and 6 is 30.
Number of marbles that Pierre has more than Tim
= 19 u - 5 u
= 14 u
14 u = 154
1 u = 154 ÷ 14 = 11
|
Tim |
Pierre |
Nick |
Before |
5 u |
19 u |
6 u |
Change |
+ 10 u |
- 19 u |
+ 9 u |
After |
15 u |
0 u |
15 u |
Number of marbles that Tim has received from Pierre
= 15 u - 5 u
= 10 u
= 10 x 11
= 110
Answer(s): 110