Charlie, Peter and Bobby have some stickers. The ratios of their stickers are as follows:
Charlie : (Charlie + Peter + Bobby) = 1 : 3
Peter : (Charlie + Bobby) = 1 : 3
Bobby has 6 stickers more than Peter. In the end, Bobby gives away all he has to Peter and Charlie so that both Peter and Charlie end up with the same number of stickers, how many stickers has Peter received from Bobby?
Peter |
Bobby |
Charlie |
Total |
2x4 |
1x4 |
3x4 |
1x3 |
3x3 |
4x3 |
3 u |
5 u |
4 u |
12 u |
The total number of stickers is repeated. Make the total number of stickers the same. LCM of 3 and 4 is 12.
Number of stickers that Bobby has more than Peter
= 5 u - 3 u
= 2 u
2 u = 6
1 u = 6 ÷ 2 = 3
|
Peter |
Bobby |
Charlie |
Before |
3 u |
5 u |
4 u |
Change |
+ 3 u |
- 5 u |
+ 2 u |
After |
6 u |
0 u |
6 u |
Number of stickers that Peter has received from Bobby
= 6 u - 3 u
= 3 u
= 3 x 3
= 9
Answer(s): 9