Zeph, Sean and Gabriel have some beads. The ratios of their beads are as follows:
Zeph : (Zeph + Sean + Gabriel) = 1 : 3
Sean : (Zeph + Gabriel) = 1 : 5
Gabriel has 16 beads more than Sean. In the end, Gabriel gives away all he has to Sean and Zeph so that both Sean and Zeph end up with the same number of beads, how many beads has Sean received from Gabriel?
Sean |
Gabriel |
Zeph |
Total |
2x2 |
1x2 |
3x2 |
1x1 |
5x1 |
6x1 |
1 u |
3 u |
2 u |
6 u |
The total number of beads is repeated. Make the total number of beads the same. LCM of 3 and 6 is 6.
Number of beads that Gabriel has more than Sean
= 3 u - 1 u
= 2 u
2 u = 16
1 u = 16 ÷ 2 = 8
|
Sean |
Gabriel |
Zeph |
Before |
1 u |
3 u |
2 u |
Change |
+ 2 u |
- 3 u |
+ 1 u |
After |
3 u |
0 u |
3 u |
Number of beads that Sean has received from Gabriel
= 3 u - 1 u
= 2 u
= 2 x 8
= 16
Answer(s): 16