Ahmad, Simon and Ivan have some beads. The ratios of their beads are as follows:
Ahmad : (Ahmad + Simon + Ivan) = 1 : 5
Simon : (Ahmad + Ivan) = 1 : 3
Ivan has 24 beads more than Simon. In the end, Ivan gives away all he has to Simon and Ahmad so that both Simon and Ahmad end up with the same number of beads, how many beads has Simon received from Ivan?
Simon |
Ivan |
Ahmad |
Total |
4x4 |
1x4 |
5x4 |
1x5 |
3x5 |
4x5 |
5 u |
11 u |
4 u |
20 u |
The total number of beads is repeated. Make the total number of beads the same. LCM of 5 and 4 is 20.
Number of beads that Ivan has more than Simon
= 11 u - 5 u
= 6 u
6 u = 24
1 u = 24 ÷ 6 = 4
|
Simon |
Ivan |
Ahmad |
Before |
5 u |
11 u |
4 u |
Change |
+ 5 u |
- 11 u |
+ 6 u |
After |
10 u |
0 u |
10 u |
Number of beads that Simon has received from Ivan
= 10 u - 5 u
= 5 u
= 5 x 4
= 20
Answer(s): 20