Tim, Neave and Will have some buttons. The ratios of their buttons are as follows:
Tim : (Tim + Neave + Will) = 2 : 5
Neave : (Tim + Will) = 1 : 5
Will has 48 buttons more than Neave. In the end, Will gives away all he has to Neave and Tim so that both Neave and Tim end up with the same number of buttons, how many buttons has Tim received from Will?
Neave |
Will |
Tim |
Total |
3x6 |
2x6 |
5x6 |
1x5 |
5x5 |
6x5 |
5 u |
13 u |
12 u |
30 u |
The total number of buttons is repeated. Make the total number of buttons the same. LCM of 5 and 6 is 30.
Number of buttons that Will has more than Neave
= 13 u - 5 u
= 8 u
8 u = 48
1 u = 48 ÷ 8 = 6
|
Neave |
Will |
Tim |
Before |
5 u |
13 u |
12 u |
Change |
+ 10 u |
- 13 u |
+ 3 u |
After |
15 u |
0 u |
15 u |
Number of buttons that Tim has received from Will
= 15 u - 12 u
= 3 u
= 3 x 6
= 18
Answer(s): 18