Brandon, Jenson and Owen have some pens. The ratios of their pens are as follows:
Brandon : (Brandon + Jenson + Owen) = 3 : 7
Jenson : (Brandon + Owen) = 1 : 3
Owen has 10 pens more than Jenson. In the end, Owen gives away all he has to Jenson and Brandon so that both Jenson and Brandon end up with the same number of pens, how many pens has Jenson received from Owen?
Jenson |
Owen |
Brandon |
Total |
4x4 |
3x4 |
7x4 |
1x7 |
3x7 |
4x7 |
7 u |
9 u |
12 u |
28 u |
The total number of pens is repeated. Make the total number of pens the same. LCM of 7 and 4 is 28.
Number of pens that Owen has more than Jenson
= 9 u - 7 u
= 2 u
2 u = 10
1 u = 10 ÷ 2 = 5
|
Jenson |
Owen |
Brandon |
Before |
7 u |
9 u |
12 u |
Change |
+ 7 u |
- 9 u |
+ 2 u |
After |
14 u |
0 u |
14 u |
Number of pens that Jenson has received from Owen
= 14 u - 7 u
= 7 u
= 7 x 5
= 35
Answer(s): 35