Dylan, Cole and Albert have some stickers. The ratios of their stickers are as follows:
Dylan : (Dylan + Cole + Albert) = 1 : 4
Cole : (Dylan + Albert) = 1 : 4
Albert has 28 stickers more than Cole. In the end, Albert gives away all he has to Cole and Dylan so that both Cole and Dylan end up with the same number of stickers, how many stickers has Cole received from Albert?
Cole |
Albert |
Dylan |
Total |
3x5 |
1x5 |
4x5 |
1x4 |
4x4 |
5x4 |
4 u |
11 u |
5 u |
20 u |
The total number of stickers is repeated. Make the total number of stickers the same. LCM of 4 and 5 is 20.
Number of stickers that Albert has more than Cole
= 11 u - 4 u
= 7 u
7 u = 28
1 u = 28 ÷ 7 = 4
|
Cole |
Albert |
Dylan |
Before |
4 u |
11 u |
5 u |
Change |
+ 6 u |
- 11 u |
+ 5 u |
After |
10 u |
0 u |
10 u |
Number of stickers that Cole has received from Albert
= 10 u - 4 u
= 6 u
= 6 x 4
= 24
Answer(s): 24