Luis, Zeph and Cole have some cards. The ratios of their cards are as follows:
Luis : (Luis + Zeph + Cole) = 3 : 7
Zeph : (Luis + Cole) = 1 : 3
Cole has 10 cards more than Zeph. In the end, Cole gives away all he has to Zeph and Luis so that both Zeph and Luis end up with the same number of cards, how many cards has Luis received from Cole?
Zeph |
Cole |
Luis |
Total |
4x4 |
3x4 |
7x4 |
1x7 |
3x7 |
4x7 |
7 u |
9 u |
12 u |
28 u |
The total number of cards is repeated. Make the total number of cards the same. LCM of 7 and 4 is 28.
Number of cards that Cole has more than Zeph
= 9 u - 7 u
= 2 u
2 u = 10
1 u = 10 ÷ 2 = 5
|
Zeph |
Cole |
Luis |
Before |
7 u |
9 u |
12 u |
Change |
+ 7 u |
- 9 u |
+ 2 u |
After |
14 u |
0 u |
14 u |
Number of cards that Luis has received from Cole
= 14 u - 12 u
= 2 u
= 2 x 5
= 10
Answer(s): 10