Gabriel, Oscar and Bryan have some stickers. The ratios of their stickers are as follows:
Gabriel : (Gabriel + Oscar + Bryan) = 1 : 4
Oscar : (Gabriel + Bryan) = 1 : 4
Bryan has 49 stickers more than Oscar. In the end, Bryan gives away all he has to Oscar and Gabriel so that both Oscar and Gabriel end up with the same number of stickers, how many stickers has Gabriel received from Bryan?
Oscar |
Bryan |
Gabriel |
Total |
3x5 |
1x5 |
4x5 |
1x4 |
4x4 |
5x4 |
4 u |
11 u |
5 u |
20 u |
The total number of stickers is repeated. Make the total number of stickers the same. LCM of 4 and 5 is 20.
Number of stickers that Bryan has more than Oscar
= 11 u - 4 u
= 7 u
7 u = 49
1 u = 49 ÷ 7 = 7
|
Oscar |
Bryan |
Gabriel |
Before |
4 u |
11 u |
5 u |
Change |
+ 6 u |
- 11 u |
+ 5 u |
After |
10 u |
0 u |
10 u |
Number of stickers that Gabriel has received from Bryan
= 10 u - 5 u
= 5 u
= 5 x 7
= 35
Answer(s): 35