Ahmad, Billy and Seth have some buttons. The ratios of their buttons are as follows:
Ahmad : (Ahmad + Billy + Seth) = 2 : 5
Billy : (Ahmad + Seth) = 1 : 3
Seth has 14 buttons more than Billy. In the end, Seth gives away all he has to Billy and Ahmad so that both Billy and Ahmad end up with the same number of buttons, how many buttons has Ahmad received from Seth?
Billy |
Seth |
Ahmad |
Total |
3x4 |
2x4 |
5x4 |
1x5 |
3x5 |
4x5 |
5 u |
7 u |
8 u |
20 u |
The total number of buttons is repeated. Make the total number of buttons the same. LCM of 5 and 4 is 20.
Number of buttons that Seth has more than Billy
= 7 u - 5 u
= 2 u
2 u = 14
1 u = 14 ÷ 2 = 7
|
Billy |
Seth |
Ahmad |
Before |
5 u |
7 u |
8 u |
Change |
+ 5 u |
- 7 u |
+ 2 u |
After |
10 u |
0 u |
10 u |
Number of buttons that Ahmad has received from Seth
= 10 u - 8 u
= 2 u
= 2 x 7
= 14
Answer(s): 14