Julian, Vincent and John have some coins. The ratios of their coins are as follows:
Julian : (Julian + Vincent + John) = 1 : 4
Vincent : (Julian + John) = 1 : 4
John has 42 coins more than Vincent. In the end, John gives away all he has to Vincent and Julian so that both Vincent and Julian end up with the same number of coins, how many coins has Julian received from John?
Vincent |
John |
Julian |
Total |
3x5 |
1x5 |
4x5 |
1x4 |
4x4 |
5x4 |
4 u |
11 u |
5 u |
20 u |
The total number of coins is repeated. Make the total number of coins the same. LCM of 4 and 5 is 20.
Number of coins that John has more than Vincent
= 11 u - 4 u
= 7 u
7 u = 42
1 u = 42 ÷ 7 = 6
|
Vincent |
John |
Julian |
Before |
4 u |
11 u |
5 u |
Change |
+ 6 u |
- 11 u |
+ 5 u |
After |
10 u |
0 u |
10 u |
Number of coins that Julian has received from John
= 10 u - 5 u
= 5 u
= 5 x 6
= 30
Answer(s): 30