When Xuan was 46 years old, her daughter was 4 times her son's age. Xuan would be twice her daughter's age when her son was 25 years old. How old would Xuan be when her son was 9 years old?
|
Xuan |
Daughter |
Son |
Before |
46 |
4 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
25 |
The difference in the ages between Xuan and her daughter remains unchanged.
Difference in Xuan's and her daughter's ages at first
46 - 4 u = 2 p - 1 p
46 - 4 u =
1 p --- (1)
The difference in the ages between her daughter and her son remains unchanged.
Difference in her daughter's and her son's ages at first
4 u - 1 u = 1 p - 25
3 u + 25 =
1 p --- (2)
Make p the same.
(1) = (2)
46 - 4 u = 3 u + 25
3 u + 4 u = 46 - 25
7 u = 21
1 u = 21 ÷ 7 = 3
Age difference between Xuan and her son
= 46 - 1 u
= 46 - 3
= 43
Xuan's age when her son was 9 years old
= 43 + 9
= 52
Answer(s): 52