When Mary was 37 years old, her son was 3 times her daughter's age. Mary would be twice her son's age when her daughter was 27 years old. How old would Mary be when her daughter was 23 years old?
|
Mary |
Son |
Daughter |
Before |
37 |
3 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
27 |
The difference in the ages between Mary and her son remains unchanged.
Difference in Mary's and her son's ages at first
37 - 3 u = 2 p - 1 p
37 - 3 u =
1 p --- (1)
The difference in the ages between her son and her daughter remains unchanged.
Difference in her son's and her daughter's ages at first
3 u - 1 u = 1 p - 27
2 u + 27 =
1 p --- (2)
Make p the same.
(1) = (2)
37 - 3 u = 2 u + 27
2 u + 3 u = 37 - 27
5 u = 10
1 u = 10 ÷ 5 = 2
Age difference between Mary and her daughter
= 37 - 1 u
= 37 - 2
= 35
Mary's age when her daughter was 23 years old
= 35 + 23
= 58
Answer(s): 58