When Gabby was 32 years old, her daughter was 2 times her son's age. Gabby would be twice her daughter's age when her son was 20 years old. How old would Gabby be when her son was 3 years old?
|
Gabby |
Daughter |
Son |
Before |
32 |
2 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
20 |
The difference in the ages between Gabby and her daughter remains unchanged.
Difference in Gabby's and her daughter's ages at first
32 - 2 u = 2 p - 1 p
32 - 2 u =
1 p --- (1)
The difference in the ages between her daughter and her son remains unchanged.
Difference in her daughter's and her son's ages at first
2 u - 1 u = 1 p - 20
1 u + 20 =
1 p --- (2)
Make p the same.
(1) = (2)
32 - 2 u = 1 u + 20
1 u + 2 u = 32 - 20
3 u = 12
1 u = 12 ÷ 3 = 4
Age difference between Gabby and her son
= 32 - 1 u
= 32 - 4
= 28
Gabby's age when her son was 3 years old
= 28 + 3
= 31
Answer(s): 31