When Tammy was 28 years old, her son was 2 times her daughter's age. Tammy would be twice her son's age when her daughter was 22 years old. How old would Tammy be when her daughter was 19 years old?
|
Tammy |
Son |
Daughter |
Before |
28 |
2 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
22 |
The difference in the ages between Tammy and her son remains unchanged.
Difference in Tammy's and her son's ages at first
28 - 2 u = 2 p - 1 p
28 - 2 u =
1 p --- (1)
The difference in the ages between her son and her daughter remains unchanged.
Difference in her son's and her daughter's ages at first
2 u - 1 u = 1 p - 22
1 u + 22 =
1 p --- (2)
Make p the same.
(1) = (2)
28 - 2 u = 1 u + 22
1 u + 2 u = 28 - 22
3 u = 6
1 u = 6 ÷ 3 = 2
Age difference between Tammy and her daughter
= 28 - 1 u
= 28 - 2
= 26
Tammy's age when her daughter was 19 years old
= 26 + 19
= 45
Answer(s): 45