When Kimberly was 46 years old, her daughter was 2 times her son's age. Kimberly would be twice her daughter's age when her son was 22 years old. How old would Kimberly be when her son was 13 years old?
|
Kimberly |
Daughter |
Son |
Before |
46 |
2 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
22 |
The difference in the ages between Kimberly and her daughter remains unchanged.
Difference in Kimberly's and her daughter's ages at first
46 - 2 u = 2 p - 1 p
46 - 2 u =
1 p --- (1)
The difference in the ages between her daughter and her son remains unchanged.
Difference in her daughter's and her son's ages at first
2 u - 1 u = 1 p - 22
1 u + 22 =
1 p --- (2)
Make p the same.
(1) = (2)
46 - 2 u = 1 u + 22
1 u + 2 u = 46 - 22
3 u = 24
1 u = 24 ÷ 3 = 8
Age difference between Kimberly and her son
= 46 - 1 u
= 46 - 8
= 38
Kimberly's age when her son was 13 years old
= 38 + 13
= 51
Answer(s): 51