When Jean was 48 years old, her daughter was 2 times her son's age. Jean would be twice her daughter's age when her son was 33 years old. How old would Jean be when her son was 14 years old?
|
Jean |
Daughter |
Son |
Before |
48 |
2 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
33 |
The difference in the ages between Jean and her daughter remains unchanged.
Difference in Jean's and her daughter's ages at first
48 - 2 u = 2 p - 1 p
48 - 2 u =
1 p --- (1)
The difference in the ages between her daughter and her son remains unchanged.
Difference in her daughter's and her son's ages at first
2 u - 1 u = 1 p - 33
1 u + 33 =
1 p --- (2)
Make p the same.
(1) = (2)
48 - 2 u = 1 u + 33
1 u + 2 u = 48 - 33
3 u = 15
1 u = 15 ÷ 3 = 5
Age difference between Jean and her son
= 48 - 1 u
= 48 - 5
= 43
Jean's age when her son was 14 years old
= 43 + 14
= 57
Answer(s): 57