When Sarah was 47 years old, her son was 3 times her daughter's age. Sarah would be twice her son's age when her daughter was 32 years old. How old would Sarah be when her daughter was 21 years old?
|
Sarah |
Son |
Daughter |
Before |
47 |
3 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
32 |
The difference in the ages between Sarah and her son remains unchanged.
Difference in Sarah's and her son's ages at first
47 - 3 u = 2 p - 1 p
47 - 3 u =
1 p --- (1)
The difference in the ages between her son and her daughter remains unchanged.
Difference in her son's and her daughter's ages at first
3 u - 1 u = 1 p - 32
2 u + 32 =
1 p --- (2)
Make p the same.
(1) = (2)
47 - 3 u = 2 u + 32
2 u + 3 u = 47 - 32
5 u = 15
1 u = 15 ÷ 5 = 3
Age difference between Sarah and her daughter
= 47 - 1 u
= 47 - 3
= 44
Sarah's age when her daughter was 21 years old
= 44 + 21
= 65
Answer(s): 65