When Natalie was 50 years old, her son was 3 times her daughter's age. Natalie would be twice her son's age when her daughter was 20 years old. How old would Natalie be when her daughter was 12 years old?
|
Natalie |
Son |
Daughter |
Before |
50 |
3 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
20 |
The difference in the ages between Natalie and her son remains unchanged.
Difference in Natalie's and her son's ages at first
50 - 3 u = 2 p - 1 p
50 - 3 u =
1 p --- (1)
The difference in the ages between her son and her daughter remains unchanged.
Difference in her son's and her daughter's ages at first
3 u - 1 u = 1 p - 20
2 u + 20 =
1 p --- (2)
Make p the same.
(1) = (2)
50 - 3 u = 2 u + 20
2 u + 3 u = 50 - 20
5 u = 30
1 u = 30 ÷ 5 = 6
Age difference between Natalie and her daughter
= 50 - 1 u
= 50 - 6
= 44
Natalie's age when her daughter was 12 years old
= 44 + 12
= 56
Answer(s): 56