When Nora was 31 years old, her son was 3 times her daughter's age. Nora would be twice her son's age when her daughter was 21 years old. How old would Nora be when her daughter was 2 years old?
|
Nora |
Son |
Daughter |
Before |
31 |
3 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
21 |
The difference in the ages between Nora and her son remains unchanged.
Difference in Nora's and her son's ages at first
31 - 3 u = 2 p - 1 p
31 - 3 u =
1 p --- (1)
The difference in the ages between her son and her daughter remains unchanged.
Difference in her son's and her daughter's ages at first
3 u - 1 u = 1 p - 21
2 u + 21 =
1 p --- (2)
Make p the same.
(1) = (2)
31 - 3 u = 2 u + 21
2 u + 3 u = 31 - 21
5 u = 10
1 u = 10 ÷ 5 = 2
Age difference between Nora and her daughter
= 31 - 1 u
= 31 - 2
= 29
Nora's age when her daughter was 2 years old
= 29 + 2
= 31
Answer(s): 31