When Raeann was 30 years old, her daughter was 2 times her son's age. Raeann would be twice her daughter's age when her son was 24 years old. How old would Raeann be when her son was 5 years old?
|
Raeann |
Daughter |
Son |
Before |
30 |
2 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
24 |
The difference in the ages between Raeann and her daughter remains unchanged.
Difference in Raeann's and her daughter's ages at first
30 - 2 u = 2 p - 1 p
30 - 2 u =
1 p --- (1)
The difference in the ages between her daughter and her son remains unchanged.
Difference in her daughter's and her son's ages at first
2 u - 1 u = 1 p - 24
1 u + 24 =
1 p --- (2)
Make p the same.
(1) = (2)
30 - 2 u = 1 u + 24
1 u + 2 u = 30 - 24
3 u = 6
1 u = 6 ÷ 3 = 2
Age difference between Raeann and her son
= 30 - 1 u
= 30 - 2
= 28
Raeann's age when her son was 5 years old
= 28 + 5
= 33
Answer(s): 33