When Tina was 36 years old, her son was 2 times her daughter's age. Tina would be twice her son's age when her daughter was 24 years old. How old would Tina be when her daughter was 5 years old?
|
Tina |
Son |
Daughter |
Before |
36 |
2 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
24 |
The difference in the ages between Tina and her son remains unchanged.
Difference in Tina's and her son's ages at first
36 - 2 u = 2 p - 1 p
36 - 2 u =
1 p --- (1)
The difference in the ages between her son and her daughter remains unchanged.
Difference in her son's and her daughter's ages at first
2 u - 1 u = 1 p - 24
1 u + 24 =
1 p --- (2)
Make p the same.
(1) = (2)
36 - 2 u = 1 u + 24
1 u + 2 u = 36 - 24
3 u = 12
1 u = 12 ÷ 3 = 4
Age difference between Tina and her daughter
= 36 - 1 u
= 36 - 4
= 32
Tina's age when her daughter was 5 years old
= 32 + 5
= 37
Answer(s): 37