When Vanessa was 41 years old, her daughter was 4 times her son's age. Vanessa would be twice her daughter's age when her son was 27 years old. How old would Vanessa be when her son was 18 years old?
|
Vanessa |
Daughter |
Son |
Before |
41 |
4 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
27 |
The difference in the ages between Vanessa and her daughter remains unchanged.
Difference in Vanessa's and her daughter's ages at first
41 - 4 u = 2 p - 1 p
41 - 4 u =
1 p --- (1)
The difference in the ages between her daughter and her son remains unchanged.
Difference in her daughter's and her son's ages at first
4 u - 1 u = 1 p - 27
3 u + 27 =
1 p --- (2)
Make p the same.
(1) = (2)
41 - 4 u = 3 u + 27
3 u + 4 u = 41 - 27
7 u = 14
1 u = 14 ÷ 7 = 2
Age difference between Vanessa and her son
= 41 - 1 u
= 41 - 2
= 39
Vanessa's age when her son was 18 years old
= 39 + 18
= 57
Answer(s): 57