When Roshel was 50 years old, her son was 4 times her daughter's age. Roshel would be twice her son's age when her daughter was 29 years old. How old would Roshel be when her daughter was 23 years old?
|
Roshel |
Son |
Daughter |
Before |
50 |
4 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
29 |
The difference in the ages between Roshel and her son remains unchanged.
Difference in Roshel's and her son's ages at first
50 - 4 u = 2 p - 1 p
50 - 4 u =
1 p --- (1)
The difference in the ages between her son and her daughter remains unchanged.
Difference in her son's and her daughter's ages at first
4 u - 1 u = 1 p - 29
3 u + 29 =
1 p --- (2)
Make p the same.
(1) = (2)
50 - 4 u = 3 u + 29
3 u + 4 u = 50 - 29
7 u = 21
1 u = 21 ÷ 7 = 3
Age difference between Roshel and her daughter
= 50 - 1 u
= 50 - 3
= 47
Roshel's age when her daughter was 23 years old
= 47 + 23
= 70
Answer(s): 70