When Roshel was 44 years old, her son was 5 times her daughter's age. Roshel would be twice her son's age when her daughter was 26 years old. How old would Roshel be when her daughter was 16 years old?
|
Roshel |
Son |
Daughter |
Before |
44 |
5 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
26 |
The difference in the ages between Roshel and her son remains unchanged.
Difference in Roshel's and her son's ages at first
44 - 5 u = 2 p - 1 p
44 - 5 u =
1 p --- (1)
The difference in the ages between her son and her daughter remains unchanged.
Difference in her son's and her daughter's ages at first
5 u - 1 u = 1 p - 26
4 u + 26 =
1 p --- (2)
Make p the same.
(1) = (2)
44 - 5 u = 4 u + 26
4 u + 5 u = 44 - 26
9 u = 18
1 u = 18 ÷ 9 = 2
Age difference between Roshel and her daughter
= 44 - 1 u
= 44 - 2
= 42
Roshel's age when her daughter was 16 years old
= 42 + 16
= 58
Answer(s): 58