When Zoe was 48 years old, her son was 2 times her daughter's age. Zoe would be twice her son's age when her daughter was 36 years old. How old would Zoe be when her daughter was 9 years old?
|
Zoe |
Son |
Daughter |
Before |
48 |
2 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
36 |
The difference in the ages between Zoe and her son remains unchanged.
Difference in Zoe's and her son's ages at first
48 - 2 u = 2 p - 1 p
48 - 2 u =
1 p --- (1)
The difference in the ages between her son and her daughter remains unchanged.
Difference in her son's and her daughter's ages at first
2 u - 1 u = 1 p - 36
1 u + 36 =
1 p --- (2)
Make p the same.
(1) = (2)
48 - 2 u = 1 u + 36
1 u + 2 u = 48 - 36
3 u = 12
1 u = 12 ÷ 3 = 4
Age difference between Zoe and her daughter
= 48 - 1 u
= 48 - 4
= 44
Zoe's age when her daughter was 9 years old
= 44 + 9
= 53
Answer(s): 53