When Lynn was 43 years old, her daughter was 3 times her son's age. Lynn would be twice her daughter's age when her son was 33 years old. How old would Lynn be when her son was 25 years old?
|
Lynn |
Daughter |
Son |
Before |
43 |
3 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
33 |
The difference in the ages between Lynn and her daughter remains unchanged.
Difference in Lynn's and her daughter's ages at first
43 - 3 u = 2 p - 1 p
43 - 3 u =
1 p --- (1)
The difference in the ages between her daughter and her son remains unchanged.
Difference in her daughter's and her son's ages at first
3 u - 1 u = 1 p - 33
2 u + 33 =
1 p --- (2)
Make p the same.
(1) = (2)
43 - 3 u = 2 u + 33
2 u + 3 u = 43 - 33
5 u = 10
1 u = 10 ÷ 5 = 2
Age difference between Lynn and her son
= 43 - 1 u
= 43 - 2
= 41
Lynn's age when her son was 25 years old
= 41 + 25
= 66
Answer(s): 66