When Kimberly was 43 years old, her son was 2 times her daughter's age. Kimberly would be twice her son's age when her daughter was 28 years old. How old would Kimberly be when her daughter was 14 years old?

	Kimberly	Son	Daughter
Before	43	2 u	1 u
Change	+ ?	+ ?	+ ?
After	2 p	1 p	28

The difference in the ages between Kimberly and her son remains unchanged.

Difference in Kimberly's and her son's ages at first
43 - 2 u = 2 p - 1 p
43 - 2 u = 1 p --- (1)

The difference in the ages between her son and her daughter remains unchanged.

Difference in her son's and her daughter's ages at first
2 u - 1 u = 1 p - 28
1 u + 28 = 1 p --- (2)

Make p the same.

(1) = (2)
43 - 2 u = 1 u + 28
1 u + 2 u = 43 - 28
3 u = 15

1 u = 15 ÷ 3 = 5

Age difference between Kimberly and her daughter
= 43 - 1 u
= 43 - 5
= 38

Kimberly's age when her daughter was 14 years old
= 38 + 14
= 52

Answer(s): 52