When Penelope was 38 years old, her daughter was 4 times her son's age. Penelope would be twice her daughter's age when her son was 24 years old. How old would Penelope be when her son was 25 years old?
|
Penelope |
Daughter |
Son |
Before |
38 |
4 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
24 |
The difference in the ages between Penelope and her daughter remains unchanged.
Difference in Penelope's and her daughter's ages at first
38 - 4 u = 2 p - 1 p
38 - 4 u =
1 p --- (1)
The difference in the ages between her daughter and her son remains unchanged.
Difference in her daughter's and her son's ages at first
4 u - 1 u = 1 p - 24
3 u + 24 =
1 p --- (2)
Make p the same.
(1) = (2)
38 - 4 u = 3 u + 24
3 u + 4 u = 38 - 24
7 u = 14
1 u = 14 ÷ 7 = 2
Age difference between Penelope and her son
= 38 - 1 u
= 38 - 2
= 36
Penelope's age when her son was 25 years old
= 36 + 25
= 61
Answer(s): 61