When Lynn was 35 years old, her daughter was 3 times her son's age. Lynn would be twice her daughter's age when her son was 20 years old. How old would Lynn be when her son was 13 years old?
|
Lynn |
Daughter |
Son |
Before |
35 |
3 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
20 |
The difference in the ages between Lynn and her daughter remains unchanged.
Difference in Lynn's and her daughter's ages at first
35 - 3 u = 2 p - 1 p
35 - 3 u =
1 p --- (1)
The difference in the ages between her daughter and her son remains unchanged.
Difference in her daughter's and her son's ages at first
3 u - 1 u = 1 p - 20
2 u + 20 =
1 p --- (2)
Make p the same.
(1) = (2)
35 - 3 u = 2 u + 20
2 u + 3 u = 35 - 20
5 u = 15
1 u = 15 ÷ 5 = 3
Age difference between Lynn and her son
= 35 - 1 u
= 35 - 3
= 32
Lynn's age when her son was 13 years old
= 32 + 13
= 45
Answer(s): 45