When Lynn was 39 years old, her son was 2 times her daughter's age. Lynn would be twice her son's age when her daughter was 24 years old. How old would Lynn be when her daughter was 4 years old?
|
Lynn |
Son |
Daughter |
Before |
39 |
2 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
24 |
The difference in the ages between Lynn and her son remains unchanged.
Difference in Lynn's and her son's ages at first
39 - 2 u = 2 p - 1 p
39 - 2 u =
1 p --- (1)
The difference in the ages between her son and her daughter remains unchanged.
Difference in her son's and her daughter's ages at first
2 u - 1 u = 1 p - 24
1 u + 24 =
1 p --- (2)
Make p the same.
(1) = (2)
39 - 2 u = 1 u + 24
1 u + 2 u = 39 - 24
3 u = 15
1 u = 15 ÷ 3 = 5
Age difference between Lynn and her daughter
= 39 - 1 u
= 39 - 5
= 34
Lynn's age when her daughter was 4 years old
= 34 + 4
= 38
Answer(s): 38