When Olivia was 46 years old, her son was 4 times her daughter's age. Olivia would be twice her son's age when her daughter was 25 years old. How old would Olivia be when her daughter was 13 years old?
|
Olivia |
Son |
Daughter |
Before |
46 |
4 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
25 |
The difference in the ages between Olivia and her son remains unchanged.
Difference in Olivia's and her son's ages at first
46 - 4 u = 2 p - 1 p
46 - 4 u =
1 p --- (1)
The difference in the ages between her son and her daughter remains unchanged.
Difference in her son's and her daughter's ages at first
4 u - 1 u = 1 p - 25
3 u + 25 =
1 p --- (2)
Make p the same.
(1) = (2)
46 - 4 u = 3 u + 25
3 u + 4 u = 46 - 25
7 u = 21
1 u = 21 ÷ 7 = 3
Age difference between Olivia and her daughter
= 46 - 1 u
= 46 - 3
= 43
Olivia's age when her daughter was 13 years old
= 43 + 13
= 56
Answer(s): 56