When Raeann was 41 years old, her daughter was 2 times her son's age. Raeann would be twice her daughter's age when her son was 23 years old. How old would Raeann be when her son was 25 years old?

	Raeann	Daughter	Son
Before	41	2 u	1 u
Change	+ ?	+ ?	+ ?
After	2 p	1 p	23

The difference in the ages between Raeann and her daughter remains unchanged.

Difference in Raeann's and her daughter's ages at first
41 - 2 u = 2 p - 1 p
41 - 2 u = 1 p --- (1)

The difference in the ages between her daughter and her son remains unchanged.

Difference in her daughter's and her son's ages at first
2 u - 1 u = 1 p - 23
1 u + 23 = 1 p --- (2)

Make p the same.

(1) = (2)
41 - 2 u = 1 u + 23
1 u + 2 u = 41 - 23
3 u = 18

1 u = 18 ÷ 3 = 6

Age difference between Raeann and her son
= 41 - 1 u
= 41 - 6
= 35

Raeann's age when her son was 25 years old
= 35 + 25
= 60

Answer(s): 60