When Risa was 38 years old, her daughter was 3 times her son's age. Risa would be twice her daughter's age when her son was 23 years old. How old would Risa be when her son was 5 years old?
|
Risa |
Daughter |
Son |
Before |
38 |
3 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
23 |
The difference in the ages between Risa and her daughter remains unchanged.
Difference in Risa's and her daughter's ages at first
38 - 3 u = 2 p - 1 p
38 - 3 u =
1 p --- (1)
The difference in the ages between her daughter and her son remains unchanged.
Difference in her daughter's and her son's ages at first
3 u - 1 u = 1 p - 23
2 u + 23 =
1 p --- (2)
Make p the same.
(1) = (2)
38 - 3 u = 2 u + 23
2 u + 3 u = 38 - 23
5 u = 15
1 u = 15 ÷ 5 = 3
Age difference between Risa and her son
= 38 - 1 u
= 38 - 3
= 35
Risa's age when her son was 5 years old
= 35 + 5
= 40
Answer(s): 40