When Tiffany was 48 years old, her son was 2 times her daughter's age. Tiffany would be twice her son's age when her daughter was 33 years old. How old would Tiffany be when her daughter was 19 years old?
|
Tiffany |
Son |
Daughter |
Before |
48 |
2 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
33 |
The difference in the ages between Tiffany and her son remains unchanged.
Difference in Tiffany's and her son's ages at first
48 - 2 u = 2 p - 1 p
48 - 2 u =
1 p --- (1)
The difference in the ages between her son and her daughter remains unchanged.
Difference in her son's and her daughter's ages at first
2 u - 1 u = 1 p - 33
1 u + 33 =
1 p --- (2)
Make p the same.
(1) = (2)
48 - 2 u = 1 u + 33
1 u + 2 u = 48 - 33
3 u = 15
1 u = 15 ÷ 3 = 5
Age difference between Tiffany and her daughter
= 48 - 1 u
= 48 - 5
= 43
Tiffany's age when her daughter was 19 years old
= 43 + 19
= 62
Answer(s): 62