When Shiyun was 36 years old, her son was 2 times her daughter's age. Shiyun would be twice her son's age when her daughter was 27 years old. How old would Shiyun be when her daughter was 18 years old?
|
Shiyun |
Son |
Daughter |
Before |
36 |
2 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
27 |
The difference in the ages between Shiyun and her son remains unchanged.
Difference in Shiyun's and her son's ages at first
36 - 2 u = 2 p - 1 p
36 - 2 u =
1 p --- (1)
The difference in the ages between her son and her daughter remains unchanged.
Difference in her son's and her daughter's ages at first
2 u - 1 u = 1 p - 27
1 u + 27 =
1 p --- (2)
Make p the same.
(1) = (2)
36 - 2 u = 1 u + 27
1 u + 2 u = 36 - 27
3 u = 9
1 u = 9 ÷ 3 = 3
Age difference between Shiyun and her daughter
= 36 - 1 u
= 36 - 3
= 33
Shiyun's age when her daughter was 18 years old
= 33 + 18
= 51
Answer(s): 51