When Shiyun was 38 years old, her daughter was 2 times her son's age. Shiyun would be twice her daughter's age when her son was 29 years old. How old would Shiyun be when her son was 5 years old?
|
Shiyun |
Daughter |
Son |
Before |
38 |
2 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
29 |
The difference in the ages between Shiyun and her daughter remains unchanged.
Difference in Shiyun's and her daughter's ages at first
38 - 2 u = 2 p - 1 p
38 - 2 u =
1 p --- (1)
The difference in the ages between her daughter and her son remains unchanged.
Difference in her daughter's and her son's ages at first
2 u - 1 u = 1 p - 29
1 u + 29 =
1 p --- (2)
Make p the same.
(1) = (2)
38 - 2 u = 1 u + 29
1 u + 2 u = 38 - 29
3 u = 9
1 u = 9 ÷ 3 = 3
Age difference between Shiyun and her son
= 38 - 1 u
= 38 - 3
= 35
Shiyun's age when her son was 5 years old
= 35 + 5
= 40
Answer(s): 40