When Elyse was 42 years old, her son was 2 times her daughter's age. Elyse would be twice her son's age when her daughter was 27 years old. How old would Elyse be when her daughter was 4 years old?
|
Elyse |
Son |
Daughter |
Before |
42 |
2 u |
1 u |
Change |
+ ? |
+ ? |
+ ? |
After |
2 p |
1 p |
27 |
The difference in the ages between Elyse and her son remains unchanged.
Difference in Elyse's and her son's ages at first
42 - 2 u = 2 p - 1 p
42 - 2 u =
1 p --- (1)
The difference in the ages between her son and her daughter remains unchanged.
Difference in her son's and her daughter's ages at first
2 u - 1 u = 1 p - 27
1 u + 27 =
1 p --- (2)
Make p the same.
(1) = (2)
42 - 2 u = 1 u + 27
1 u + 2 u = 42 - 27
3 u = 15
1 u = 15 ÷ 3 = 5
Age difference between Elyse and her daughter
= 42 - 1 u
= 42 - 5
= 37
Elyse's age when her daughter was 4 years old
= 37 + 4
= 41
Answer(s): 41