Lee bought some lemons and pears in the ratio of 1 : 3 . After buying another 10 fruits each, the ratio becomes 5 : 11. Find the number of lemons and pears he had at first.
| |
Lemons |
Pears |
Difference |
| Before |
1x3 =
3 u |
3x3 =
9 u |
2x3 =
6 u |
| Change |
+ 10 |
+ 10 |
|
| After |
5x1 =
5 u |
11x1 =
11 u |
6x1 =
6 u |
Since the same number of fruits bought for each type of fruits is the same, the difference in the number of lemons and pears at first and in the end remains unchanged.
Make the difference in the number of lemons and pears the same. LCM of 2 and 6 is 6.
Increase in the number of lemons
= 5 u - 3 u
= 2 u
2 u = 10
1 u = 10 ÷ 2 = 5
Number of pears and lemons that Lee had at first
= 3 u + 9 u
= 12 u
= 12 x 5
= 60
Answer(s): 60
