Cole bought some pears and kiwis in the ratio of 1 : 4 . After buying another 138 fruits each, the ratio becomes 8 : 9. Find the number of pears and kiwis he has now.
| |
Pears |
Kiwis |
Difference |
| Before |
1x1 =
1 u |
4x1 =
4 u |
3x1 =
3 u |
| Change |
+ 138 |
+ 138 |
|
| After |
8x3 =
24 u |
9x3 =
27 u |
1x3 =
3 u |
Since the same number of fruits bought for each type of fruits is the same, the difference in the number of pears and kiwis at first and in the end remains unchanged.
Make the difference in the number of pears and kiwis the same. LCM of 3 and 1 is 3.
Increase in the number of pears
= 24 u - 1 u
= 23 u
23 u = 138
1 u = 138 ÷ 23 = 6
Number of kiwis and pears that $(Fred) has now
= 24 u + 27 u
= 51 u
= 51 x 6
= 306
Answer(s): 306
