Sean bought some peaches and pomegranates in the ratio of 1 : 4 . After buying another 57 fruits each, the ratio becomes 7 : 9. Find the number of peaches and pomegranates he has now.
| |
Peaches |
Pomegranates |
Difference |
| Before |
1x2 =
2 u |
4x2 =
8 u |
3x2 =
6 u |
| Change |
+ 57 |
+ 57 |
|
| After |
7x3 =
21 u |
9x3 =
27 u |
2x3 =
6 u |
Since the same number of fruits bought for each type of fruits is the same, the difference in the number of peaches and pomegranates at first and in the end remains unchanged.
Make the difference in the number of peaches and pomegranates the same. LCM of 3 and 2 is 6.
Increase in the number of peaches
= 21 u - 2 u
= 19 u
19 u = 57
1 u = 57 ÷ 19 = 3
Number of pomegranates and peaches that $(Fred) has now
= 21 u + 27 u
= 48 u
= 48 x 3
= 144
Answer(s): 144
