Sean bought some kiwis and chikoos in the ratio of 1 : 5 . After buying another 92 fruits each, the ratio becomes 7 : 12. Find the number of kiwis and chikoos he has now.
| |
Kiwis |
Chikoos |
Difference |
| Before |
1x5 =
5 u |
5x5 =
25 u |
4x5 =
20 u |
| Change |
+ 92 |
+ 92 |
|
| After |
7x4 =
28 u |
12x4 =
48 u |
5x4 =
20 u |
Since the same number of fruits bought for each type of fruits is the same, the difference in the number of kiwis and chikoos at first and in the end remains unchanged.
Make the difference in the number of kiwis and chikoos the same. LCM of 4 and 5 is 20.
Increase in the number of kiwis
= 28 u - 5 u
= 23 u
23 u = 92
1 u = 92 ÷ 23 = 4
Number of chikoos and kiwis that $(Fred) has now
= 28 u + 48 u
= 76 u
= 76 x 4
= 304
Answer(s): 304
