Simon bought some chikoos and passion fruits in the ratio of 1 : 3 . After buying another 45 fruits each, the ratio becomes 8 : 9. Find the number of chikoos and passion fruits he had at first.
| |
Chikoos |
Passion Fruits |
Difference |
| Before |
1x1 =
1 u |
3x1 =
3 u |
2x1 =
2 u |
| Change |
+ 45 |
+ 45 |
|
| After |
8x2 =
16 u |
9x2 =
18 u |
1x2 =
2 u |
Since the same number of fruits bought for each type of fruits is the same, the difference in the number of chikoos and passion fruits at first and in the end remains unchanged.
Make the difference in the number of chikoos and passion fruits the same. LCM of 2 and 1 is 2.
Increase in the number of chikoos
= 16 u - 1 u
= 15 u
15 u = 45
1 u = 45 ÷ 15 = 3
Number of passion fruits and chikoos that Simon had at first
= 1 u + 3 u
= 4 u
= 4 x 3
= 12
Answer(s): 12
