Albert bought some pears and peaches in the ratio of 1 : 4 . After buying another 12 fruits each, the ratio becomes 5 : 11. Find the number of pears and peaches he had at first.
| |
Pears |
Peaches |
Difference |
| Before |
1x2 =
2 u |
4x2 =
8 u |
3x2 =
6 u |
| Change |
+ 12 |
+ 12 |
|
| After |
5x1 =
5 u |
11x1 =
11 u |
6x1 =
6 u |
Since the same number of fruits bought for each type of fruits is the same, the difference in the number of pears and peaches at first and in the end remains unchanged.
Make the difference in the number of pears and peaches the same. LCM of 3 and 6 is 6.
Increase in the number of pears
= 5 u - 2 u
= 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of peaches and pears that Albert had at first
= 2 u + 8 u
= 10 u
= 10 x 4
= 40
Answer(s): 40
