Pierre bought some pears and mangoes in the ratio of 1 : 3 . After buying another 14 fruits each, the ratio becomes 5 : 11. Find the number of pears and mangoes he has now.
| |
Pears |
Mangoes |
Difference |
| Before |
1x3 =
3 u |
3x3 =
9 u |
2x3 =
6 u |
| Change |
+ 14 |
+ 14 |
|
| After |
5x1 =
5 u |
11x1 =
11 u |
6x1 =
6 u |
Since the same number of fruits bought for each type of fruits is the same, the difference in the number of pears and mangoes at first and in the end remains unchanged.
Make the difference in the number of pears and mangoes the same. LCM of 2 and 6 is 6.
Increase in the number of pears
= 5 u - 3 u
= 2 u
2 u = 14
1 u = 14 ÷ 2 = 7
Number of mangoes and pears that $(Fred) has now
= 5 u + 11 u
= 16 u
= 16 x 7
= 112
Answer(s): 112
