Ivan bought some chikoos and mangoes in the ratio of 1 : 3 . After buying another 20 fruits each, the ratio becomes 5 : 11. Find the number of chikoos and mangoes he has now.
| |
Chikoos |
Mangoes |
Difference |
| Before |
1x3 =
3 u |
3x3 =
9 u |
2x3 =
6 u |
| Change |
+ 20 |
+ 20 |
|
| After |
5x1 =
5 u |
11x1 =
11 u |
6x1 =
6 u |
Since the same number of fruits bought for each type of fruits is the same, the difference in the number of chikoos and mangoes at first and in the end remains unchanged.
Make the difference in the number of chikoos and mangoes the same. LCM of 2 and 6 is 6.
Increase in the number of chikoos
= 5 u - 3 u
= 2 u
2 u = 20
1 u = 20 ÷ 2 = 10
Number of mangoes and chikoos that $(Fred) has now
= 5 u + 11 u
= 16 u
= 16 x 10
= 160
Answer(s): 160
