Mark bought some grapefruits and peaches in the ratio of 1 : 3 . After buying another 44 fruits each, the ratio becomes 7 : 10. Find the number of grapefruits and peaches he had at first.
| |
Grapefruits |
Peaches |
Difference |
| Before |
1x3 =
3 u |
3x3 =
9 u |
2x3 =
6 u |
| Change |
+ 44 |
+ 44 |
|
| After |
7x2 =
14 u |
10x2 =
20 u |
3x2 =
6 u |
Since the same number of fruits bought for each type of fruits is the same, the difference in the number of grapefruits and peaches at first and in the end remains unchanged.
Make the difference in the number of grapefruits and peaches the same. LCM of 2 and 3 is 6.
Increase in the number of grapefruits
= 14 u - 3 u
= 11 u
11 u = 44
1 u = 44 ÷ 11 = 4
Number of peaches and grapefruits that Mark had at first
= 3 u + 9 u
= 12 u
= 12 x 4
= 48
Answer(s): 48
