Pierre bought some starfruits and kiwis in the ratio of 1 : 4 . After buying another 46 fruits each, the ratio becomes 8 : 9. Find the number of starfruits and kiwis he had at first.
| |
Starfruits |
Kiwis |
Difference |
| Before |
1x1 =
1 u |
4x1 =
4 u |
3x1 =
3 u |
| Change |
+ 46 |
+ 46 |
|
| After |
8x3 =
24 u |
9x3 =
27 u |
1x3 =
3 u |
Since the same number of fruits bought for each type of fruits is the same, the difference in the number of starfruits and kiwis at first and in the end remains unchanged.
Make the difference in the number of starfruits and kiwis the same. LCM of 3 and 1 is 3.
Increase in the number of starfruits
= 24 u - 1 u
= 23 u
23 u = 46
1 u = 46 ÷ 23 = 2
Number of kiwis and starfruits that Pierre had at first
= 1 u + 4 u
= 5 u
= 5 x 2
= 10
Answer(s): 10
